Respuesta :

gmany

Answer:

[tex]\large\boxed{x\approx32}[/tex]

Step-by-step explanation:

Use sine:

[tex]sine=\dfrac{opposite}{hypotenuse}[/tex]

We have

[tex]opposite=10\\hypotenuse=19[/tex]

Substitute:

[tex]\sin x^o=\dfrac{10}{19}\approx0.5263\to x\aaprox32^o[/tex]