A sample of gas occupies a volume of 120.0 mL at a pressure of 0.75 atm and a temperature of 295 K. What will the volume be at a pressure of 1.25 atm and a temperature of 345 K?
The answer to the question is 84 (Step By Step Explanation). P1 V1/T1= P2 V2/T2 ::0.75 x 120/295 = 1.25 x V2/345 90/295= 1.25V2/345 (cross multiply ) 1.25V2 x 295 = 90 x 345 368.75V2 = 31050 (divide by the coefficient of the unknown) . 368.75V2/368.75 = 31050/368.75 V2 = 84.2. = 84 ::The volume is 82. Mark As brainliest
