Answer:
In case (a) car makes 105° turn.
In case (b) car makes 75° turn.
In case (c) car makes 105° turn.
Step-by-step explanation:
Figure is redrawn To explain properly (in attachment)
Given : streets are parallel means [tex]\overline{AB}[/tex] â•‘ [tex]\overline{CD}[/tex],
       AB - 4th street , CD - 3rd street and XY - King Ave.
      ∠XLA = 75°
To find : (a) ∠XLB
       (b) ∠LMD (left onto 3rd streat means left of car)
       (c) ∠YMD (right means right side of car)
∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are Â
                   supplementary)
∠XLB + 75° = 180°
∠XLB  = 180 - 75
∠XLB = 105°
∴ In case (a) car makes 105° turn.
∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)
∠LMD = 75°
∴ In case (b) car makes 75° turn.
∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are
                    supplementary)
∠YMD + 75° = 180°
∠YMD = 180 - 75
∠YMD = 105°
∴In case (c) car makes 105° turn.