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Julian fully simplifies this polynomial and then writes it in standard form.

4x2y2 – 2y4 – 8xy3 + 9x3y + 6y4 – 2xy3 – 3x4 + x2y2

If Julian wrote the last term as –3x4, which must be the first term of his polynomial in standard form?

a) 4y4
b) 6y4
c) –2xy3
d) –10xy3

Relax

Respuesta :

Answer:

4y^4

Step-by-step explanation:

[tex]4x^2y^2 - 2y^4 - 8xy^3 + 9x^3y + 6y^4 - 2xy^3 - 3x^4 + x^2y^2[/tex]

Last term is -3x^4

This means x term is increasing and it ends at x^4

we arrange the terms in order

[tex]6y^4- 2y^4 - 8xy^3 - 2xy^3 +4x^2y^2+ x^2y^2 + 9x^3y-3x^4[/tex]

now we combine like terms

[tex]4y^4 - 10xy^3 +5x^2y^2 + 9x^3y -3x^4[/tex]

So first term is 4y^4

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