José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be removed without the riders falling. When the ride accelerates to a speed of 17.0 m/s, his angular momentum is 3570 kg m2/s. What is his mass?

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits

Relax

Respuesta :

r = radius of the circle of the ride = 3.00 meters

v = linear speed of the person during the ride = 17.0 m/s

m = mass of the person in angular motion in the ride

L = angular momentum of the person in the ride = 3570 kg m²/s

Angular momentum is given as

L = m v r

inserting the values

3570 kg m²/s = m (17 m/s) (3.00 m)

m = 3570 kg m²/s/(51 m²/s)

m = 7 kg

hence the mass comes out to be 7 kg


Answer:

70.0 kg

Explanation:

L = mvr

You are solving for m so you change the equation to equal m

m = (L)/vr

m = (3570)/(17)(3)

m = 3570/51

m = 70

His mass is 70 kg.