The enthalpy  of  combustion  of magnesium  is -601.3  kj/mol
calculation
 ΔH = cΔT
  C( heat capacity) =5,760 j/°c
  ΔT = 0.570°c
 ΔH = 5760 j/°c  x 0.570 °c = 3283.2 j
convert 3283.2 j into Kj
1 kj = 1000 j
 kj ?  =3283.2 j
 by cross multiplication
={ (3283.2  j  x 1 kj) / 1000 j}  =3.2832 kj
Find the  moles of Mg
moles = mass÷ molar mass Â
from periodic table the molar mass  of Mg = 24.3 g/mol
= 0.1326 g÷ 24.3 g/mol =0.00546 moles
find ΔH in KJ/mol
 =  3.2832 kj/ 0.00546 moles = 601.3 Kj/mol
since  heat  is released during combustion the ΔH  is  = - 601.3 kj/mol
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