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Write an equation in point-slope form for the line through the given point with the given slope. (-10, -6);m=-5/8

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The point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

We have the slope [tex]m=-\dfrac{5}{8}[/tex] and the point (-10, -6). Substitute:

[tex]y-(-6)=-\dfrac{5}{8}(x-(-10))\\\\\boxed{y+6=-\dfrac{5}{8}(x+10)}[/tex]