The formula of a volume of a cone:
[tex]V_1=\dfrac{1}{3}\pi r^2H[/tex]
We have 2r = 8 in → r = 4in and H = 18 in. Substitute:
[tex]V_1=\dfrac{1}{3}\pi(4^2)(18)=\pi(16)(6)=96\pi\ ni^3[/tex]
The fomula of a volume of a cylinder:
[tex]V_2=\pi r^2H[/tex]
We have 2r = 8 in → r = 4 in and H = 3 in. Substitute:
[tex]V_2=\pi(4^2)(3)=\pi(16)(3)=48\pi\ in^3[/tex]
[tex]V_2:V_1=48\pi:96\pi=1:2[/tex]
The volume of the cylinder is twice as large as the volume of the cone.
