a waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day. anither day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49. how much did each type of dinner cost?

a) the cost of ribeye steak dinners is $

b) the cost of salmon dinners is $

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Blacklash Blacklash · Answer 1 · 2018-11-22T11:59:12+01:00

Answer:

a) The cost of ribeye steak dinners is $ 16.96.

b) The cost of grilled salmon dinners is $ 23.37.

Explanation:

Let the cost for ribeye steak dinners be m and cost for grilled salmon dinners be n.

A waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day.

So, we have

10 m + 18 n = 590.39 -------equation 1

Another day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49

So, we have

22 m + 9 n = 583.49 -------equation 2

equation 2 x 2

44 m + 18 n = 1166.98 -------equation 3

equation 3 - equation 1

44 m + 18 n - ( 10 m + 18 n ) = 1166.98 - 590.39

m = 16.96 $

Substituting in equation 1

22 x 16.96 + 9 n = 583.49

n = 23.37 $

a) The cost of ribeye steak dinners is $ 16.96.

b) The cost of grilled salmon dinners is $ 23.37.