The ionization energy is the energy needed to remove an electron from an atom. In the bohr model of the hydrogen atom, this means exciting the electron to the n = ∞ state. What is the ionization energy in kj/mol, for hydrogen atoms initially in the n = 2 energy level?

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znk znk · Answer 1 · 2018-09-22T02:33:51+02:00

The ionization energy for a hydrogen atom in the n = 2 state is 328 kJ·mol⁻¹.

The first ionization energy of hydrogen is 1312.0 kJ·mol⁻¹.

Thus, H atoms in the n = 1 state have an energy of -1312.0 kJ·mol⁻¹ and an energy of 0 when n = ∞.

According to Bohr, Eₙ = k/n².

If n = 1, E₁= k/1² = k = -1312.0 kJ·mol⁻¹.

If n = 2, E₂ = k/2² = k/4 = (-1312.0 kJ·mol⁻¹)/4 = -328 kJ·mol⁻¹

∴ The ionization energy from n = 2 is 328 kJ·mol⁻¹ .

adioabiola adioabiola · Answer 2 · 2021-10-12T14:41:08+02:00

The ionization energy in Kj/mol, for hydrogen atoms initially in the n=2 energy level is;

-5.45 × 10^(-22) J/mol.

According to Bohr's atomic model, the ionization energy of an hydrogen atom is related to the energy level of the atoms as follows;

E = k/n²

where E = ionization energy

k = first ionization energy of hydrogen =

-2.18 × 10^(-18).

and n = energy level = 2

Therefore, the ionization energy of hydrogen atoms in the energy.

E = {-2.18 × 10^(-18)}/2².

E = -5.45 × 10^(-19) J/mol

E = -5.45 × 10^(-22) J/mol.

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