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a ball of mass 4 kg is initially traveling at 2 meters per second and has a 5 Newton Force applied to it for 3 seconds what's the final velocity of the ball

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[tex] a=\frac{F}{m}=\frac{5N}{4kg}=1.2\frac{m}{s^2} [/tex]

[tex] \Delta v = a \cdot t = 1.2 \frac{m}{s^2} \cdot 3 s = 3.6 \frac{m}{s} [/tex]

[tex] v = v_0 + \Delta v = 2 + 3.6 = 5.6 \frac{m}{s} [/tex]

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