Relax

Respuesta :

check the picture below.

so, then using the pythagorean theorem, we can get "b", namely the height of the trapezoid.

[tex]\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\ ---------\\ a=3\\ b=\stackrel{1+4}{5}\\ h=\sqrt{8} \end{cases}\implies A=\cfrac{\sqrt{8}(3+5)}{2} \\\\\\ A=\cfrac{8\sqrt{8}}{2}~~ \begin{cases} 8=2\cdot 2\cdot 2\\ \qquad 2^2\cdot 2 \end{cases}\implies A=\cfrac{8\sqrt{2^2\cdot 2}}{2}\implies A=\cfrac{8\cdot 2\sqrt{2}}{2} \\\\\\ A=\cfrac{16\sqrt{2}}{2}\implies A=8\sqrt{2}[/tex]
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