Jazzyfwae
Jazzyfwae
15-05-2018
Mathematics
contestada
Rewrite with only sin x and cos x. Sin2x-cos2x
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sbcardinals
sbcardinals
15-05-2018
From trig identities, we know that sin2x = 2sinxcosx and cos2x = [tex]cos^{2} x - sin^{2} x[/tex]
So sin2x-cos2x =
2sinxcosx - ([tex]cos^{2} x - sin^{2} x[/tex])
in terms of sinx and cosx
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