Respuesta :
As in this problem the order of numbers does not matter We are talking about a combination and not to permutation.
 So to determine the probability that a set of six randomly selected numbers wins the lottery we need to first draw the combination of 6 in 49 without repetition:
 C (49.6) = 49! / (6! (49-6)!) = 13983816
 Then there are 13983816 combinations of possible numbers for this case.
 Finally the probability is:
 p = 1/13983816
 p = 7,151 x10 ^ -8
 The correct option is the last
 So to determine the probability that a set of six randomly selected numbers wins the lottery we need to first draw the combination of 6 in 49 without repetition:
 C (49.6) = 49! / (6! (49-6)!) = 13983816
 Then there are 13983816 combinations of possible numbers for this case.
 Finally the probability is:
 p = 1/13983816
 p = 7,151 x10 ^ -8
 The correct option is the last