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The sum of three numbers is 62. The second number is equal to the first number diminished by 4. The third number is four times the first. What are the numbers?

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Hey there!

Let: 1st number = x
       2nd number = x - 4
       3rd number = 4x 

x + (x-4) + 4x = 62
6x - 4 = 62
6x = 62 + 4
6x = 66

x = 11 ---> 1st number

x - 4 = 11 - 4 
        = 7  ---> 2nd number 

4x = 4(11)
     = 44 ---> 3rd number 

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