The equilibrium constant, K, for the following reaction is 1.20×10⁻² at 500 K.
PCl₅(g) <----> PCl₃(g) + Cl₂(g)
An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.288 M PCl₅, 5.88×10⁻² M PCl₃ and 5.88×10⁻² M Cl₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 5.17×10⁻² mol of Cl₂(g) is added to the flask?