Evaluate the indefinite integral by using the substitution: \(\int \frac{(\sqrt{x}-4)^6}{2\sqrt{x}}dx\)

A. \(\int \frac{(\sqrt{x}-4)^7}{14}dx\)
B. \(\int \frac{(\sqrt{x}-4)^5}{10}dx\)
C. \(\int \frac{(\sqrt{x}-4)^7}{7}dx\)
D. \(\int \frac{(\sqrt{x}-4)^5}{14}dx\)