The recursive formula for a sequence of numbers is shown:
a1=β14
an=anβ1β5
Which equation would produce the same sequence of numbers as the recursive formula shown?
an= a1 + (nβ1)d
Responses:
f(n)=β9nβ5f of n is equal to negative 9 n minus 5
f(n)=β9β5nf of n is equal to negative 9 minus 5 n
f(n)=14f of n is equal to 14
f(n)=nβ5