Medunno13 Medunno13

12-10-2022
Mathematics

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Let [tex]ABC[/tex] be a right triangle with [tex]\angle BCA=90^{\circ}[/tex]. A circle with diameter [tex]AC[/tex] intersects the hypotenuse [tex]AB[/tex] at [tex]K[/tex]. If [tex]BK:AK=1:3[/tex], find [tex]\angle BAC[/tex].

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